Displaying A Multidimensional Array

Hi guys, I just had a simple question, one of my homework assignments was to write a multidimensional array that displays the elements of that array that are larger than all their neighbors.
The problem is, when I use a function I made myself to attempt to give a visual of the array, I get the number -858993460 in place of what should be there. The rest of the program however works fine. I'm kinda stumed here, any help is appreciated. Here's the code I'm using:

Code:

---

/*
*File: neighbors.c
*The program creates a multidimensional array, and then displays the elements of that
*array that are larger than all their neighbors.
*/

#include "stdafx.h"
#include <stdio.h>
#include "genlib.h"
#include "simpio.h"

#define size 5

void getArray(int ne[][size]);
bool check_neighbors(int ne[][size],int i,int j);
void displayArray(int ne[][size]);

main()
{
        int ne[size][size],i,j;
        getArray(ne);
        printf("Your array is:\n");
        displayArray(ne);
        for(i=1;i<size-1;i++)
        {
                for (j=1;j<size-1;j++)
                {
                        if (check_neighbors(ne,i,j)==true) printf("%d in location (%d,%d)\n",ne[i][j],i-1,j-1);
                }
        }
}

void getArray(int ne[][size])
{
        int i,j;
        for(i=1;i<size-1;i++)
        {
                for (j=1;j<size-1;j++)
                {
                        printf("\nEnter next integer:  ");
                        ne[i][j]=GetInteger();
                }
        }
}

void displayArray(int ne[][size])
{
        int i,j;
        for (i=1;i<size-1;i++);
        {
                for (j=1;j<=size-1;j++)
                {
                        printf("%4d",(ne[i][j]));
                }
                printf("\n");
        }
}

bool check_neighbors(int ne[][size],int i,int j)
{
        if ((ne[i+1][j+1]<=ne[i][j])&&(ne[i-1][j-1]<=ne[i][j])&&(ne[i+1][j]<=ne[i][j])&&(ne[i][j+1]<=ne[i][j])&&(ne[i-1][j]<=ne[i][j])&&(ne[i][j-1]<=ne[i][j])&&(ne[i+1][j-1]<=ne[i][j])&&(ne[i-1][j+1]<=ne[i][j]))
        {
                return (true);
        }
        else return(false);
}

---

Again, thanks for any help

Arrays start at zero, not one. So for your size of 5, you have valid array elements 0,1,2,3 and 4.


Quzah.

Yeah, I understand that the array starts at one, but I only want to display the 3x3 set of values that is in the center of the array. The other two rows are only present to make it easier for me to use the check_neighbors function I created, so that I wouldn't have to alter it or add unnecessary ifs into it for values with less than eight neighbors, but the program still gives me the error. I was wondering more about why I might get the strange output of -858993460. Thanks again for any help.

If you do not want to display the first and last entry

Code:

---

void displayArray(int ne[][size]) {
        int i,j;
        for (i=1;i<size-1;i++);          //remove semicolon
        {
                for (j=1;j<=size-1;j++) // should be j<size-1
                {
                        printf("%4d",(ne[i][j]));
                }
                printf("\n");
        }
}

---

Kurt

> int ne[size][size]
Unless you do something, all these array elements start off with junk values.
So you need to initialise your perimeter elements with zero (for example).