count strings in an array?

Hi,

I've a two-dimensional character array, initialized as follows:

Code:

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char *valid_help_str[] = {{"help"},{"help add queue"},{"help add queue default"},{"help add queue basic"},{"help add queue medium"},{"help add queue advanced"}};

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How to count number of strings present in this array?

Thank you

If the array is in scope, you can do this

Code:

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size_t numElements = sizeof(valid_help_str) / sizeof(valid_help_str[0]);

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This does NOT work if you pass the array to a function, and try to do it inside the function.

You can add some newlines to your array you know, so we don't have to scroll horizontally as well.

You can find the size of the array and divide it by the size of a char pointer:

Code:

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#include <stdio.h>

int main( void )
{
    char *valid_help_str[] = {
        "help",
        "help add queue",
        "help add queue default",
        "help add queue basic",
        "help add queue medium",
        "help add queue advanced"
    };

    printf( "Number of elements = %lu\n", sizeof( valid_help_str ) / sizeof( char * ) );

    return 0;
}

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The output from this program is "Number of elements = 6" which is expected.

Kevin

Quote:

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Originally Posted by sangamesh

Hi,

I've a two-dimensional character array, initialized as follows:

Code:

---

char *valid_help_str[] = {{"help"},{"help add queue"},{"help add queue default"},{"help add queue basic"},{"help add queue medium"},{"help add queue advanced"}};

---

How to count number of strings present in this array?

Thank you

---

Since you are simply assigning string constants, there should be no reason to count anything... you should already know how many strings *you programmed* into the array.