expression execution order

I'd like to call a number of functions, all which can only be called if the previous function succeeded. All functions return bool results, so just wondering what the best way to do this would be.

I'm currently using the following method:

Code:

---

if (func_a())
  if (func_b())
      if (func_c())
(etc...)

---

but wondering if this would be better:

Code:

---

if (func_a() && func_b() && func_c())

---

Problem is, would they all be called regardless of whether the previous one failed, or would execution stop when one of them returned FALSE? Or worse still, is the above unspecified, and depends on compiler?

Use your first method

The second method may not work in all compilers (if any), the first method is easier to read, debug, and maintain.

The evaluation order of && and || is defined, otherwise things like

if ( p && *p != 0 )
would randomly fail if p was a NULL pointer

So
if (func_a() && func_b() && func_c())
would stop as soon as one of the funcs returned false, and those calls to the right would NOT happen.

Ok, thanks. Much appreciated!