static array list

I'm trying to make static list that can add element in list. I know that's know the good way to make list but it's just experiment

only 5 digits allow in list

Program supposed to give result like this

add digit 1 in array then show array = 1
add digit 2 in array then show array = 1 2
add digit 3 in array then show array = 1 2 3
add digit 4 in array then show array = 1 2 3 4
add digit 5 in array then show array = 1 2 3 4 5


When array exceed limit size, stop adding digit

Code:

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#include<stdio.h>


int main ()
{
        int i;
       
        int array[5];
       
        return 0;
}

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I need a function that add one digit in array and show the array digits

I'm stuck with function I don't understand what's logic need to add one digit

To add first digit => array[0] = 1
To add second digit => array[1] = 2
and so on until 5th digit which will be in array[4]

To print the array use a simple for loop.

Quote:

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Originally Posted by thmm

To add first digit => array[0] = 1
To add second digit => array[1] = 2
and so on until 5th digit which will be in array[4]

To print the array use a simple for loop.

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I can do that but I am looking for a function

Code:

---

#include<stdio.h>

int main ()
{
        int i;
       
        int array[5] = {1};
       
        for ( i = 0; i <5; i++)
                printf(" %d", array[i]);
           
                array[1] = 2;
       
    printf("\n");
       
        for ( i = 0; i <5; i++)
                printf(" %d", array[i]);
       
                array[2] = 3;
       
    printf("\n");
       
        for ( i = 0; i <5; i++)
                printf(" %d", array[i]);
       
            array[3] = 4;
       
    printf("\n");
       
        for ( i = 0; i <5; i++)
                printf(" %d", array[i]);
       
       
      array[4] = 5;
       
    printf("\n");
       
        for ( i = 0; i <5; i++)
                printf(" %d", array[i]);
       
        return 0;
}

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1 0 0 0 0
1 2 0 0 0
1 2 3 0 0
1 2 3 4 0
1 2 3 4 5

Maybe:

Code:

---

#include <stdio.h>
 
void push(int *a, int *size, int value) {
    a[(*size)++] = value;
}
 
void print(const int *a, int size) {
    while (size-- > 0) printf("%d ", *a++);
    putchar('\n');
}
 
#define CAPACITY 5
 
int main() {
    int a[CAPACITY], size = 0;
    for (int i = 1; i <= CAPACITY; ++i) {
        push(a, &size, i);
        print(a, size);
    }
    return 0;
}

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Quote:

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Originally Posted by john.c

Maybe:

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How do you do if number is not in sequence ?

2
2 9
2 9 3
2 9 3 6
2 9 3 6 5

Push whatever values you want. I just used a counting loop.