Math help?

I have the following code:

Code:

---

#include <msp430.h>#include "stdlib.h"
#include "stdio.h"


    const char frq[8], br[8];
    long f, b;
    char *frqPtr, *brPtr;
    int d;
    float interim;


void main()
{
    strcpy(frq, "16000000");
    strcpy(br, "115200");
    f = atol(frq);
    b = atol(br);
    interim = f/b/16;
    d = (int)((interim - (int)interim) * 16);
}

---

After I run I get the following from the debugger:
interim float 8.0 0x002018
d int 0 0x00201C
f long 16000000 0x002014
b long 115200 0x002010

Can someone tell me how to get interim = 8.68055555556 and d = 10?

Problem solved: change f, b to float and cast

Are you sure? The final value must be 8.6805553436279296875 in single precision (8.68055555556 cannot be represented in any floating point precision).

> void main()
main returns an int.

> strcpy(frq, "16000000");
1. You don't include string.h
2. frq is declared const, so you can't copy to it.
3. frq isn't large enough anyway, so buffer overflow.