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this code: http://pastebin.com/f168570c8
gives the compile error:
test_templates.cpp: In function 'int main(int, char**)':
test_templates.cpp:51: error: expected `(' before 'g'
test_templates.cpp:51: error: expected `)' before ';' token
test_templates.cpp:51: error: invalid const_cast from type 'bar<lab2::Gregorian>' to type 'bar<lab2::Julian>*'
where the Julian and Gregorian are date classes that inherit from Date
How do I "make" the variable j as if it was of <template> type Georgian?
1) templ<Bar> is completely unrelated to templ<Foo>, even if Foo and Bar are in an inheritance relationship. There can be no conversion between the two that is not explicitly specified by the template.
2) You cannot const_cast between different types. Only between cv-qualified versions of one type.
3) You cannot cast an object to a pointer type. Especially not with const_cast.
4) Casting between Gregorian and Julian calenders does not make sense. You can perhaps convert between them, but it would be a really bad idea to have the conversion implicit.
5) C++ cast expressions (the *_cast<> things) need parentheses around the argument.