make a program stay....

i was writing a program to demonstrate how ports are accessed using c. i am using the parmon (parallel port monitor) to see the counting (see program). but every time i send the program window to the back (using wimdiws98...turbo c for compiling), the program halts and resumes only afer the window is activated again. how do i make te program keep running even if i send its program window to the back?

here's the prog:

Code:

---

#include <stdio.h>
#include <conio.h>
#include <dos.h>

#define base 0x378

void main()
{
unsigned char i=0;
char ch;

clrscr();
printf("Press <ESC> to exit the program");

fflush(stdin);

do
{
outportb (base , i);
i++;
delay (1000);
if (kbhit())
        ch=getch();
}while (ch!=27);

printf("\nBYE!!!");
getch();
}

---

Try this:

Code:

---

#include <stdlib.h>
int main()
{
system(“PAUSE”);
return 0;
}

---

doesnt work!!!

>fflush(stdin);
Don't use this. Check the FAQ: http://faq.cprogramming.com/cgi-bin/...&id=1043284351

As for your question regarding the window. If you were using say a dialog box there is probably a Windows API to make it active. Not sure for a DOS console window.

- Sean

When putting a DOS box into the background on Win98, the process is paused. I don't know if there is a way around that, but it will have nothing to do with your program. It's an OS function.

Maybe a property of the window will allow the program to continue. If not, try searching google. If it can be done, the great googly-moogly will know.

there has to be a way.....comeon!!!

Quote:

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Originally posted by Nirav
there has to be a way.....comeon!!!

---

There is:
1) Upgrade to XP
2) Use Linux
3) Call Microsoft and have them fix Win98

Sheesh!