Problem with printing a maze...

Hi,

THe printing part of my maze program doesn't work. So i picked out the part that doens't work ( below ). It should print 12 characters per column and per row, however it doesn't. Pls help. THnx in advance!

Code:

---

/* Prints a maze */

#include <stdio.h>

void printMaze( char maze[][ 12 ] );

int main()
{
  int maze[ 12 ][ 12 ] = { '1', '1', '1', '1', '1', '1', '1', '1', '1', '1', '1', '1',  /* 0 */
                            '1', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1',  /* 1 */
                            '0', '0', '1', '0', '1', '0', '1', '1', '1', '1', '0', '1',  /* 2 */
                            '1', '1', '1', '0', '1', '0', '0', '0', '0', '1', '0', '1',  /* 3 */
                            '1', '0', '0', '0', '0', '1', '1', '1', '0', '1', '0', '0',  /* 4 */
                            '1', '1', '1', '1', '0', '1', '0', '1', '0', '1', '0', '1',  /* 5 */
                            '1', '0', '0', '1', '0', '1', '0', '1', '0', '1', '0', '1',  /* 6 */
                            '1', '1', '0', '1', '0', '1', '0', '1', '0', '1', '0', '1',  /* 7 */
                            '1', '0', '0', '0', '0', '0', '0', '0', '0', '1', '0', '1',  /* 8 */
                            '1', '1', '1', '1', '1', '1', '0', '1', '1', '1', '0', '1',  /* 9 */
                            '1', '0', '0', '0', '0', '0', '0', '1', '0', '0', '0', '1',  /* 10 */
                            '1', '1', '1', '1', '1', '1', '1', '1', '1', '1', '1', '1' };/* 11 */

  printMaze( maze );

  getch();
  return 0;
}

void printMaze( char maze[][ 12 ] )
{
  int i, j;

  printf( "\n\n" );

  for ( i = 0; i < 12; i++ )
      for ( j = 0; j < 12; j++ ) {
        if ( j == 11 )
            printf( "\n" );
        printf( "%c", maze[ i ][ j ] );
      }
}

---

Make sure "maze" is defined as either an integer or a char array (you have it as int where you define it and char in the function you pass it to). I would say char is the way to go here.

Also, put your statement to print a newline AFTER you print the array character... otherwise the last character of the line gets shifted to the next line and the whole maze gets thrown off.

Hope that helps.

> printf( "%c", maze[ i ][ j ] );

You're printing a character when maze is declared as an integer array.

Code:

---

void printMaze( int maze[][ 12 ] );
void printMaze( int maze[][ 12 ] )
{
  int i, j;
  printf( "\n\n" );
  for ( i = 0; i < 12; i++ ) {
      for ( j = 0; j < 12; j++ ) {
        printf( "%c", maze[ i ][ j ] );
      }
      printf( "\n" );
  }
}

---

Your compiler must have generated a warning about incompatible types - surely

If he makes it "int" and leaves the single quotes in the array declaration/definition, won't he end up with the integer equivalent of the CHARACTER 1 and 0 versus the number itself?

Please let me know if I'm way off on that. Thanks.

Sorry... that was very presumptuous (sp?) of me. He OR she...

> won't he end up with the integer equivalent of the CHARACTER 1 and 0 versus the number itself?
Which is exactly what you want, when your're printing them using %c in a printf statement