getopt - multiple instances of an option

if I'm using getopt, and I'm checking for a bunch of options, how do I differentiate between one instance of an option and multiple instances?

// Scan the arguments and set flags.
opterr = FALSE;
for (;;) {
int option = getopt (argc, argv, "nxyd:@:");
if (option == EOF) break;
switch (option) {
case 'd': user_dictionary = optarg;
break;
case 'n': default_dictionary = NULL;
break;
// want to check for -x or -xx
case 'x': STUBPRINTF ("-x\n");
break;
case 'y': yy_flex_debug = TRUE;
break;
case '@': set_debugflags (optarg);
if (strpbrk (optarg, "@y")) yy_flex_debug = TRUE;
break;
default : eprintf ("%: -%c: invalid option\n", optopt);
set_exitstatus (EXIT_FAILURE);
};
};

1. You including <unistd.h> ?
2. What do you mean by single or multiple instances?

I am including <unistd.h>

I'm mean I want to check if there is -x or -xx. I want to do different things for those two different cases, but I'm not sure how.

According to my knowledge as option is an integer and you can only differentiate multiple instances of an integer by dividing and getting remainder and quotients logic....

In this case, you will have to simplify it like that....

Problem??

Why don't you try this..

Code:

---


int option = getopt (argc, argv, "nxyd:@:-x:-xx");

---

okay, I'll try it, thank you.

The easiest way would be:

Code:

---

int c;
int xflag = 0;

while((c = getopt(argc, argv, "x")) != -1)
{
  switch(c)
  {
    case 'x':
      xflag++;
      break;
  }
}

---

Now xflag contains the number of times the -x option has been given.

Note also that getopt() is defined as returning -1 when it's done, not EOF. EOF is generally -1, but need not be.