Array for malloc needed

I am trying to allocate the memory of 1KB of size to two variables. I treied with for loop, but i am getting segmentation fault error. I have attached my sample code below. can anyone help to find why that error occurs and whats the solution for my problem

Code:

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#include<stdio.h>
#include<stdlib.h>
main()
{
 int i,*par[i];
                                                                                                                           
  for(i=0;i<=2;i++)
  {
  par[i]=(int *)malloc(1024);
  printf("\n%u",par[i]);
  }
                                                                             
  free(par);
}

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"Thanks in advance"

Code:

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int i,*par[i];

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i is not initialized.

Code:

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for(i=0;i<=2;i++)

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iterates 3 times.

Code:

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printf("\n%u",par[i]);

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%u is for unsigned ints, not pointers.

http://faq.cprogramming.com/cgi-bin/...&id=1043284351

you don't free your mallocs.

http://faq.cprogramming.com/cgi-bin/...&id=1043284376

int *par[i];
declares array of unknown size

int* par[2]; - declares array of 2 pointers

Code:

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free(par);

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This is NOT supposed to be free()ed. Each element of the array should be free()ed, however.