User input array size!!

Hi, i have an assignment to do that is: Write a program that asks the users to enter a value for array size “n” and fill up the array with n integers. Then reverse the array and print it on the screen.

I am not asking for the whole thing to be done for me, but I need help with getting the user to enter the array size. I have this so far

Code:

---

#include <stdio.h>
int main(void)
{
    int n;
    printf("Enter size of array\n");
    scanf_s("%d", &n);


    float array[n];


    for (int i = 0; i < n; i++) {
        scanf_s("%f", &array[n]);
    }


    printf("%f", array[n]);
    getchar();
    getchar();
}

---

You got correctly the data inside the array. Now you can write reverse function by using temporary array and then print the array.

This code does not work. It says "n" must have a constant value

That is because you have to have fixed array size

Code:

---

float array[100];

---

Also the declaration should come at the beginning of function.

You need to write
float *array = malloc( n * sizeof(*array) ); // synthesise float array[n];

Don't forget to include stdlib.h

Also, if you get warnings about casting void*, then stop using a C++ compiler to compile C code, by renaming your source files.


> scanf_s("%f", &array[n]);
Also, use i (your loop variable), not n (your array length).