Help with this small snippet of code?

Hello,

I am experimenting with structure and trying to assign
address of a struct type and print a members value,
but I get many errors. Please see code below;

Code:

---


#include <iostream>
using namespace std;

struct Num {
 unsigned int total;
};




void Set(struct Num *nn) {
 nn->total = 99;
}


int main () {
 struct Num spike;
 struct Num *NewPtr;


 NewPtr=&spike;
 NewPtr->total = 5;
 Set(NewPtr);
 
 printf("\ns.total =   
 %d\n", NewPtr->total);
}

---

here are errors:

compiler.cpp:60:9: warning: missing terminating " character
60 | printf("\ns.total =
| ^
compiler.cpp:60:9: error: missing terminating " character
60 | printf("\ns.total =
| ^~~~~~~~~~~~
compiler.cpp:61:4: error: stray '\' in program
61 | %d\n", NewPtr->total);
| ^
compiler.cpp:61:6: warning: missing terminating " character
61 | %d\n", NewPtr->total);
| ^
compiler.cpp:61:6: error: missing terminating " character
61 | %d\n", NewPtr->total);
| ^~~~~~~~~~~~~~~~~~
compiler.cpp: In function 'int main()':
compiler.cpp:61:2: error: expected primary-expression before '%' token
61 | %d\n", NewPtr->total);
| ^
compiler.cpp:61:3: error: 'd' was not declared in this scope
61 | %d\n", NewPtr->total);
| ^

thank you

You need to take the newline out of the middle of your string.

Code:

---

printf("\ns.total = %d\n", NewPtr->total);

---

Other things to note
1. You're writing C++ code for a C++ compiler.
2. printf is the C way to print things, you should be using cout instead.

Hello Salem,

impossible !

I am using a C/C++ compiler app which supposedly
does both!


and considered the new line in the
Printf statement consider this
code which works fine:

Code:

---

struct Num {
 unsigned int total;
}s;


int test(struct Num nn) {
 nn.total = 9;
 return 0;
}


int main () {
 s.total = 5;
 test(s);
 printf("\ns.total = %d\n", s.total);
}

---

the question is why would the latter work
and the original example fail in the
printf statement?

Thanks for replying !

Quote:

---

Originally Posted by Trying-C

impossible !

I am using a C/C++ compiler app which supposedly
does both!

---

... but not at the same time. You have to pick a language: do you want to write this program in C or in C++?

Also, read Stroustrup's answer to the FAQ: What do you think of C/C++?

As for the newline: Salem was talking about a physical newline in your string literal. Your latter code doesn't have that problem.

Hi, I want to use C.

but there is no option to choose C or C++???

and I don’t understand what you are talking
about when you say the string in the
printf statement .... I took both “\n” out of the
printf statement and still doesn’t work?!!!

oooofffff ! 😟

Quote:

---

Originally Posted by Trying-C

Hi, I want to use C.

but there is no option to choose C or C++???

---

You just haven't found it yet. What IDE and/or compiler are you using?

Quote:

---

Originally Posted by Trying-C

and I don’t understand what you are talking
about when you say the string in the
printf statement .... I took both “\n” out of the
printf statement and still doesn’t work?!!!

---

Try to compile this program:

Code:

---

#include <stdio.h>

int main(void)
{
    printf("hello
world\n");
    return 0;
}

---

You should get a compile error. Now try to compile this program:

Code:

---

#include <stdio.h>

int main(void)
{
    printf("hello\nworld\n");
    return 0;
}

---

The program should compile successfully. Then try to compile this program:

Code:

---

#include <stdio.h>

int main(void)
{
    printf("hello\
world\n");
    return 0;
}

---

The program should also compile successfully, but you will find that the output is all on one line.

The idea is that a string literal, i.e., something like "hello\nworld\n" cannot just contain a physical line break (unless you escape that line break so that the two physical lines form a single logical line, which is what the last program demonstrated). This is the issue with your original code: you typed enter when you shouldn't have. It is as simple as that.

In practice, if you do want to break a long string literal across multiple physical lines, you would take advantage of the fact that adjacent string literals ("adjacent" excluding whitespace) are concatenated during compilation, like this:

Code:

---

#include <stdio.h>

int main(void)
{
    printf("hello\n"
          "world\n");
    return 0;
}

---

> Hi, I want to use C.
> but there is no option to choose C or C++???

> compiler.cpp:
Rename this to compiler.c

Most compiler drivers recognise automatically that .c files are for the C compiler, and .cpp/.cxx are for the C++ compiler.

Quote:

---

Originally Posted by Trying-C

and I don’t understand what you are talking
about when you say the string in the
printf statement .... I took both “\n” out of the
printf statement and still doesn’t work?!!!

---

What they are talking about is that I think you accidentally hit enter in your printf() line... they aren't meaning the new line character '\n' but rather how you probably pressed enter in the middle of your "hello world" string. Your string should be on a single line with control characters to format what you want within that string. The computer won't see your entered new line in the code the same as a '\n' character.