Thread: problem with data cast

  1. #1
    Registered User
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    problem with data cast

    Hi everybody!!!!! I need to pass an int array through send() function and I do it in this way:

    server side:
    int array[10];
    char* buffer;
    buffer = (char*)malloc(20);
    buffer = (char*) array;
    send(socket, buffer, sizeof(buffer), 0);

    client side:
    int *array;
    char *buf;
    recv(socket, buf, 20, 0);
    array = (int *)buf;

    According to you, what's wrong? Data I receive have different values from those I send. Where is the problem?
    Thanks.

  2. #2
    Frequently Quite Prolix dwks's Avatar
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    array = (int *)buf ? Can recv() accept an integer parameter?
    dwk

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  3. #3
    and the hat of int overfl Salem's Avatar
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    > buffer = (char*)malloc(20);
    1. you cast malloc - this is not necessary in C - see the FAQ
    2. you seem to assume that sizeof(int) is 2. If this really is the case, your compiler is too old

    > buffer = (char*) array;
    You just lost the memory you allocated.

    > send(socket, buffer, sizeof(buffer), 0);
    1. you don't check the return result.
    2. sizeof() on a pointer gives you the size of the pointer, not the size of the thing it points at.

    result = send(socket, array, sizeof(array), 0);


    > According to you, what's wrong?
    Pretty much every line of code you've written has problems.
    Start by
    a) learning C
    b) reading all the tutorials in the announcements on this forum
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

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