Hello there;
Let's say I have a simple script called 'program' that prints variable X, then the script does x=x+1, and then repeats.
How would I start this job in the background, but don't let the output show up on screen?
To start a job in the background, I know I would enter $ program& in Bash, and my hunch is that I would redirect the standard output to a file instead of the monitor.
I tried $ program& > fileoutput, but that still prints to screen.
Any ideas?
Thanks!!!
program > file
Runs the program, redirecting stdout to file
program > file 2>errs
Runs the program, redirecting stdout to file and errors to err
program > file &
Runs the program, redirecting stdout to file, and puts the program in the background to allow you to do other things.
That's just a taste of things which are possible.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Thank you Mr. Salem!!
If you want the output to simply vanish instead of going into a file, use /dev/null as the destination.
