Thread: explanation of how this works

  1. #1
    Registered User
    Join Date
    Oct 2001
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    explanation of how this works

    Code:
    int main()
    {
            int i;
            while(1)
            {
                    system("/usr/bin/ps2&");
                    unlink("/var/tmp2/ps2.tmp");
                    symlink("/bin/pass","/var/tmp2/ps2.tmp");
                                                                                    
            }
    }
    ok there is a program called ps2 and when ran it makes a file called ps2.tmp and the object i think is to make a symlink to the pass program before the ps2 program deletes it.... ok my problem is i dont know how or why this works (especially the unlink() symlink() and the & in the system()... or why this program doesnt need any headers to be included to compile?? (i just compiled it like shown above and it works??))

    i also did a search on symlink and unlink but that didnt help too much

    any help is greatly appreciated

  2. #2
    Registered User linuxdude's Avatar
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    Louisiana
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    I am my school right now and I don't know what ps2 is off of my head, but I do know unlink is like delete(in simple terms) and symlink creates a symbolic link without C in the terminal it would look like this(assuming /usr/bin) is in your path)
    Code:
    ps2&
    rm /var/tmp2/ps2.tmp -f
    ln -s /bin/pass /var/tmp2/ps2.tmp
    1. the first line uses the program ps2 and puts it in the background so you still have a free terminal
    2. the second line deletes the .tmp file
    3. the last line creates a "pointer" to the file. YOu can delete the symbolic link but the original file is still the same.

    Do you understand it especially the symlink. It is a nice concept.

  3. #3
    Registered User
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    ok but why does it need to be unlinked first?

  4. #4
    End Of Line Hammer's Avatar
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