I've been wondering: what happens to a pointer when it's passed as a parameter to a function? Why is this:
<code>
int main(void) {
char *str;
*str = 'a';
return 0;
</code>
not legal, while this is perfectly legal:
<code>
void function(char *);
void function(char *str) {
*str = 'a';
}
int main(void) {
char *str;
function(str);
return 0;
}
</code>
Thanks
Skarr
I like traffic lights. I like traffic lights. I like traffic lights, but only when they're green.
I know that, but if I initialize the string in main() I would have a locked size for my string. And if i read stuff from (say) a file, I won't know how big tje buffer should be.
I like traffic lights. I like traffic lights. I like traffic lights, but only when they're green.
I don't think it's a good idea either way. Your char* points to garbage, so you need to point it to an actual buffer:
Code:void funct(char* buffer, int size) { /* do whatever operation you want on up to size bytes of the buffer */ } int main() { /* obviously you must define MAX_BUFFER_SIZE to something approprate somewhere */ char buffer[MAX_BUFFER_SIZE]; char* pbuffer = buffer; /* of course you could just pass buffer too */ funct(pbuffer, MAX_BUFFER_SIZE); return 0; }
