Thread: using gdb to debug.

To the next problem. My book tells me to debug the program a.out that I have written and saved. However I am not getting the same results executing the command as are given in the book. The second line is the first thing I am missing completely in my output. I also have no idea if this is spitted out or typed in my me as when I press enter after a.out my next line results in "(gdb)". The following result is what I should get:

Code:

reader:~/booksrc $ gdb -q ./a.out
Using host libthread_db library "/lib/tls/i686/cmov/libthread_db.so.1".
(gdb) break main
Breakpoint 1 at 0x804837a
(gdb) run
Starting program: /home/reader/booksrc/a.out

Breakpoint 1, 0x0804837a in main ()
(gdb) info registers
eax            0xbffff894       -1073743724
ecx            0x48e0fe81       1222704769
edx            0x1      1
ebx            0xb7fd6ff4       -1208127500
esp            0xbffff800       0xbffff800
ebp            0xbffff808       0xbffff808
esi            0xb8000ce0       -1207956256
edi            0x0      0
eip            0x804837a        0x804837a <main+6>
eflags         0x286    [ PF SF IF ]
cs             0x73     115
ss             0x7b     123
ds             0x7b     123
es             0x7b     123
fs             0x0      0
gs             0x33     51
(gdb) quit
The program is running.  Exit anyway? (y or n) y
reader:~/booksrc $

This is the result I am getting:

Code:

root:~#gdb -q ./a.out
(no debugging symbols found)
(gdb) break main
Breakpoint 1 at 0x804837a
(gdb) run
Starting program: /root/a.out
(no debugging symbols found)
(no debugging symbols found)
(no debugging symbols found)

Breakpoint 1 at 0x804837a in main ()
(gdb)

You'll probably get some information from info registers even without the symbols. But you won't get variable names, or line numbers, or a lot of anything else.

As to "Using host libthread_db library "/lib/tls/i686/cmov/libthread_db.so.1"", did you compile your program with the thread_db library?