Thread: Order of Memory Locations

Hello All,

I have the following Memory addresses .

Address of function
f1 :80483a0
f2 :80483e8
main :80483ff

Address of all the local variables in main
uila :bfedb4d4
ila :bfedb4d0
uisl :80498c8
isl :80498c0

Iam in a linux environment.

I want to know what would be increasing order ( memory locations).

To put in a simple words , i want to know how the OS gives memory locations ( address) to C / C++ programs ?

Will it vary with the 16 bit , 32 bit , 64 bit computers ?

Will this depends on the RAM of our computer ?

Does this depend on the OS we use ?

regards
vlrk

Thanks for your reply

I would like to know the increasing order of memory locations?


Address of function
f1 :80483a0
f2 :80483e8

In above case does a0 is the first one or e8 is the first one.

i want to know the offset of the memory locations .

If iam not wrong these fuctions comes into Text/Code section of the exectutable , when it loaded into memory.

Why there is difference in the heap , static and local memory locations.

If we observer the below memory locations it shows that functions, static memory variables , global variable and heap meomory variables are of only 7 digits where as local variables are of 8 digits

Code:

Output 

Address of function f1:80483a0, f2:80483e8 and main :80483ff

Address of all the local variables in main
 uila  :bffdf8e4, ila :bffdf8e0 uisl :80498c8 isl:80498c0

Address of all the global variables in main
uig1:80498cc ig1:80498b4
uig2:80498d4 ig2:80498b8
uig3:80498d0 ig3:80498bc

 Address of dynamically allocated memory : 916c008
Addresses of all the local and parameter variables of f1
Addresses of parameter variables pa:bffdf8c0 pb:bffdf8c4
Addresses of local variables x:bffdf8b4 y:bffdf8b0
Addresses of all the local and parameter variables of f1
Addresses of parameter variables pa:bffdf8b0 pb:bffdf8b4
Addresses of local variables x:bffdf8a4 y:bffdf8a0
Addresses of all the local and parameter variables of f1
Addresses of parameter variables pa:bffdf8c0 pb:bffdf8c4
Addresses of local variables x:bffdf8b4 y:bffdf8b0

is it any thing related to the 32 bit or 64 bit computers?

How to know does our system is of 32 bit or 62 bit based ?

I think even this addressing helps in knowing the 32 bit / 64 bit ..?

i feel so because at any point of time there will 8 hexa decmial bits and in binary every

hexa decimal bit is equal to four bits so 4 * 8 = 32 bits.

Am i right or wrong ?

I was just continueing the same topic .. I was refering to the address of the variables.

I should have given a bit preamble in my previous post.

One of programas variable address is as like below

Code:

uig1:080498cc

Any hexa digit is of 4 binary bits so i feel here 8 hexa digits ( each 4 binary bits )

i.e 32 binary bits.

I think even this would be helpfull in knowing , whether our system is of 32 bits / 64 bits.


If iam wrong please correct me.

Thanks for your insights.

Any way i was trying to understand , in c program how memory will be alloted by OS.

I was printing different kind of variable including the function names to understand this.

My primary idea is not of knowing 32bit etc..

regards
Rama Kanth