Is this really a loop of order n, and not perhaps of log(n)?Code:for (i=1; i<=n; i*=2)
Is this really a loop of order n, and not perhaps of log(n)?Code:for (i=1; i<=n; i*=2)
I might be wrong.
Quoted more than 1000 times (I hope).Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
