I have a book with questions at the end of each chapter, but no answers(3d Math Primer for Graphics and Game Development). I was wondering if anyone here could check my answersthanks for any help.Code:(dfdp)=dot for dot product (cfcp)=cross for cross product norm(x)=normalize vector x I. a) -[3 7] = [-3 -7] b) ||[-12 5]|| = 13 c) ||[8 -3 1/2]|| = 8.56(about) d) 3[4 -7 0] = [12 -21 0] e) [4 5]/2 = [2 2.5] II. a) norm([12 5]) = [12/13 5/13] b) norm([8 -3 1/2]) = [100/107 -75/214 25/428](about) III. a) [3 10 7] - [8 -7 4] = [-5 17 3] b) 3[a b c] - 4[2 10 -6] = [3a-8 3b-40 3b-24] IV. Compute the distance between the pairs of points a) [3 10 7],[8 -7 4] = 17.972(about) b) [10 6],[-14 30] = 33.941(about) V. a) I don't get this one. [2 6] (dfdp) -38??? b) 3[-2 0 4] (dfdp) ([8 -2 3/2] + [0 9 7]) = 78 (Could someone explain the order of precedence on this one?) VI. a) compute angle betweent the vectors [1 2] and [-6 3] = 90 VII. Given the vectors v=[4 3 -1], n=[sqrt(2)/2 sqrt(2)/2 0] separate v into components that are perpendicular and parallel to n.(n is a unit vector) I don't know how to do this one VIII. [3 10 7] (cfcp) [8 -7 4] = [89 44 -101]