I got weird outputs characters when I print

[aama100]

Problem: Printing weird characters instead of printing ID#s.

The program's function: Add a new client's name and a new ID, and then it is your choice if you want to print.

it compilers without errors

#include <iostream>
using namespace std;

class healthClubMaintain{

private:
	 string names[15];
	 string idnumbers[15];
	 int counter,counter2,i,s;
	

public:
	void addClient(string,int);
	void printClient();
	
	healthClubMaintain() {  // default constructor
    counter = 0;
	 counter2 = 0;

}

};


void healthClubMaintain::addClient(string clientName, int clientIDNumber){
	
	if (counter<15){
		names[counter]=clientName;
		counter++;
	}
	
	if (counter2<15){
		idnumbers[counter2]=clientIDNumber;
		counter2++;
	} 
		

}

void healthClubMaintain::printClient(){
		
		i=0;
		s=0;
		while(i<counter){
			cout << "client's name:  " << names[i]<<endl;
			cout << "ID#:  " << idnumbers[s]<<endl;
			i++;
			s++;
		}
		
}



int main(){

int number,loop=0;
int clientIDNumber, programNumber,approvalIDNumber,clientIDA,programNumberA;
string clientName,programName,approvalName;
healthClubMaintain Club;

while ( loop==0){

	cout<< "Select one of the following option:"<<endl;
	cout<< "(1) Add a new client to the program"<<endl;
	cout<< "(2) print"<<endl;

	cin >> number;


if ( number ==1 ){
	cout << "Insert the client's name" << endl;
	cin >> clientName;
	cout << "Insert a new ID" << endl;
	cin >>clientIDNumber;
	Club.addClient(clientName,clientIDNumber);
}

if ( number == 2){
	 Club.printClient();
}

}

}

[tabstop]

if (counter2<15){
		idnumbers[counter]=clientIDNumber;
		counter++;
	}

I'm sure you have a reason for using two completely separate counters, although I wonder what it is.

[aama100]

if (counter2<15){
		idnumbers[counter]=clientIDNumber;
		counter++;
	}

I'm sure you have a reason for using two completely separate counters, although I wonder what it is.

I fixed that and I updated the code up there but it still has weird characters appear instead of ID#s in the output

[Daved]

What kind of name are you inputting?

If there are any spaces in the name (like John Doe) it won't work. The cin >> clientName; code will only read in a word and stop at any space, tab or newline. Then when you try to read cin >>clientIDNumber; it will fail because the second part of the name will be sitting there instead of a number.

The solution is to use getline to read in the name. This will cause other small problems in your program, though. The most important problem will be that the calls to cin >> for the numbers will leave a newline in the stream that will be picked up by getline. To fix that you can simply add cin.ignore(); after and call to cin >> whatever;.