Thread: Quick Struct Question

I'm trying to make an array with the information for five employees. However it's says that my structs aren't correct. I followed the book as much as I could I must be making a dumb mistake somewhere can someone point it out. I'm getting all sorts of errors.

Code:

#include <iostream>
#include <string>
using namespace std;

struct employeeType
{
	nameType employee;
	nameType supervisor;
	dateType dob;
	dateType starting;
	float rate;
	int id_Num;
	int hours;
};

struct nameType
{
	string first;
	char mid;
	string last;
};

struct dateType
{
	int month;
	int day;
	int year;

};

Those are the new variable types. I am confused. Isn't it being declared in the name and date type... That's how the book had it lol

wow it was that the declarations had to go first lol. I am restarted at programming. Well now I can start working on my array thanks.

Code:

#include <iostream>
#include <string>
using namespace std;


const int MAX = 5;

struct nameType
{
	string first;
	char mid;
	string last;
};

struct dateType
{
	int month;
	int day;
	int year;

};

struct employeeType
{
	nameType employee;
	nameType supervisor;
	dateType dob;
	dateType starting;
	float rate;
	int id_Num;
	int hours;
};

employeeType Database[MAX];

int main()
{
	int i;

	for (i = 1; i < MAX; i++)
	{
		cout << "Please enter information for employee number " << i << ": " << endl;
		cin >> Database[i].id_Num >> Database[i].employee >> Database[i].dob >> Database[i].rate >> Database[i].hours 
			>> Database[i].starting >> Database[i].supervisor;
	}

	return 0;

}

Now I'm trying to take all of the information for five employees. Gives me this error.

"1>c:\users\doug\documents\visual studio 2008\projects\lab3\lab3\lab3.cpp(43) : error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'nameType' (or there is no acceptable conversion)"

Originally Posted by GCNDoug

Now I'm trying to take all of the information for five employees. Gives me this error.

"1>c:\users\doug\documents\visual studio 2008\projects\lab3\lab3\lab3.cpp(43) : error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'nameType' (or there is no acceptable conversion)"

So you need to write a routine that "reads in" a nameType structure. You can overload operator >>, if you want, or you can change your input to read in Database[i].employee.first, and then Database[i].employee.middle, and then Database[i].employee.last (for example). (If it were I writing it, I'd probably test it out by writing it straight in, and then turn that into an overloaded operator >>; but that may seem like way too much work right now for you.)