Thread: Keep running program and 'int' problem

Your temperature, windspeed and chill variables should all be double or float.
Since integers are whole numbers, using decimal points is inappropriate for the type int.

To keep the program running, you need to use some kind of loop. When you finish everything, ask the user if she wants to run the program again, if she enters yes, go back to the top of the loop, if she says no, terminate the loop.

It's up to you to figure out how to implement this.

Or use a sentinal controlled loop:

Code:

std::cout << "Enter a number or enter -1 to end: ";
std::cin >> number;

while ( number != -1 )
{
   std::cout << "\nSqaured: " << number * number << std::endl;

   std::cout << "Enter a number or -1 to end: ";
   std::cin >> number;
}

This snippet will continue to square the number untill the user enters -1 to exit the loop

swgh I'm pretty sure this is his homework.

Oh sorry I did not complete the program for him I just mentioned a way to use a user controlled loop thats all.

Anyway, although the type of control swgh suggested can be useful, in my opinion there is a better loop for this case.
Also, you should be careful when using != and == with floating point numbers.

Thanks, all of you. I used a while loop. Thanks carlorfeo for the tips, and thanks swgh and NeonBlack for the loop idea... I completely forgot about it...

Here is the code a the proggy working how I want it:

Code:

#include <cstdlib>
#include <iostream>
#include <math.h>

using namespace std;

int main(int argc, char *argv[])
{
    double temp, vel;
    double ch;
    char yn;
    while (yn = 1) 
    {
          cout << "Wind Chill Calculator...\n" ;
          cout << "By William Seed\n" ;
          cout << "Enter the temperature: ";
          cin >> temp;
          cout << "Enter the wind speed: ";
          cin >> vel;
          ch = 35.75 + (.6215 * temp) - (35.75 * pow(vel,.16)) + (.4275 * temp * pow(vel,.16));
          cout << "The wind chill is: ";
          cout << ch;
          cout << "\n";
          cout << "Enter 1 to rerun program: " ;
          cin >> yn ;
          cout << "\n\n";
    }

    system("PAUSE");
    return EXIT_SUCCESS;
}

I have one more question, though... It's not that important, but if I enter anything besides 1, it still reruns the program. How could I fix that?

anyway your loop won't work since you tell the program to loop while yn is 1.
Is it correct?

edit:
sorry, I didn't read the code well enough
the real matter is that the loop won't start because, when you run the program, yn is not 1: its value has not been declared.

Using while (yn = 1) worked beacause the statement (yn = 1), which is an assignment, will always result true.

It runs just fine the way it is in my previous post, but it won't exit.

I only made two changes:

I added in a second = to make it a comparison.

and

I set yn = 1 just before the while statement and after the char yn; statement, and it doesn't allow me to rerun the program at all.

Originally Posted by carlorfeo

2: Compare yn with a char -> (yn == "r")
and of course change the sentence to "Enter 'r' to rerun program: "

(yn=='r') actually. Single quotes for char and double quotes are for string.