I going to post my problem below but I really am just stuck on how to get to the byte in position bp. I know how to set the bits to 1, but just flustered on trying to get to the specified byte.
ThanksCode://Returns the unsigned int obtained when the byte in //position bp of x is set to all 1-bits //The bytes are numbered 0 to 3 from right to left. unsigned int setByte(unsigned int x, int bp) { //body }
Perhaps bitshifts can help?
I might be wrong.
Quoted more than 1000 times (I hope).Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
I was thinking about a bitshift, but I need to return x unchanged except for the byte in which all the bits are set 1, so possible bitshift a copy of x and then and it to x, but I'm really having trouble on accessing the specific byte(indicated by bp), would a loop be neccessary?
You need to set all the bits in a specific byte?
Originally Posted by Adak
I almost never use bitshifts, but this is what I am thinking
int original = 0xf0f0f0f0;
int mask = 0x0000000f;
mask = mask << 3; // Assuming you want to change the third byte.
int changed = original | mask;
I have no idea if it will actually work.
Last edited by 691175002; 01-29-2008 at 06:13 PM.
If you wanted to set the X byte, then something like this might do the trick:
Code:unsigned int setByte(unsigned int x, int bp) { int mask = 0xFF << (8 * bp); x |= mask; return x; }
Thanks alot Elysia and everyone else that got me there, I really appreciate the help!
