i have a an if statement is there a way to make multiple fuctions equal to one value? for example.
or something of that syntax im not sure what but is there any way to do this? or would i have to do each individual one seperatly?Code:if ( x == " yes "," maybe"){ a = 10; } or... if ( x == 1-10){ b = "yes"; }
thanks for the help.
you would either use && or ||, and or, or respectively. in your example it would look like.
Code:if ( x == " yes " || x == " maybe"){ a = 10; } or... if ( x >= 1 && x <= 10){ b = "yes"; }
Note that BOTH of the original code-snippets are actually valid C code. They just don't do quite what you expect. The first one is "always true" [at least if we assume the compiler doesn't place strings that have the address of "NULL" - which is true for all compilers I've ever seen].
This is because of the fairly rare "comma operator", where you can writelvalue will get the value of expr3, so in the case of the first code-snippet, the if-statement will be based on the " maybe" string - which is "true" by the C standard.Code:lvalue = expr1, expr2, expr3
The second expression compares x with -9, since 1-10 is -9.
--
Mats
Last edited by matsp; 01-17-2008 at 06:09 AM.
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
ok i was wondering if there was a way to do like:Originally Posted by matsp
1 through 5 = something
6 through 10 = something else
etc.
but i guess dracs way works also, well i havent tried yet but thanks for the help.
Code:if (x >= 1 && x <= 5) { something(); } else if (x >= 6 && x <= 10) { something_else(); }
I might be wrong.
Quoted more than 1000 times (I hope).Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
