How Can I create negative random numbers?
Will this trick do the work ?
Code:int num = rand() % 10 +1; int num2 = rand () % 10 +1; int negRandNum = num * ( - num2 );
How Can I create negative random numbers?
Will this trick do the work ?
Code:int num = rand() % 10 +1; int num2 = rand () % 10 +1; int negRandNum = num * ( - num2 );
Depending on what you actually want (your routine will never produce some integers within a range).
You can simply flip the sign of a variable: var = -var;
I might be wrong.
Quoted more than 1000 times (I hope).Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
how to flip the sign
sry for the silly q but i rly d0nt kn0
Sorry for the silly question, but I really don't understand.Originally Posted by manzoor
Kurt
anon gave an example: var = -var;
Look up a C++ Reference and learn How To Ask Questions The Smart Way
so
Code:int num = rand() % 10 + 1; int negNum = -num;
If you've got a random number between 0 and 9, what happens if you subtract 10?
That's simpler that adding 1 then flipping the sign.
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Advice: Take only as directed - If symptoms persist, please see your debugger
Linus Torvalds: "But it clearly is the only right way. The fact that everybody else does it some other way only means that they are wrong"
i really dont care about the range of random numbers
just tell me whether im flipping the sign correctly or not /
I don't know. I would have to write a small program to test it.
Kurt
This is simple algebra, not calculus...
x * -1 = -x
-x * -1 = x
If you want a positive number to be negative, just multiply by -1.
The question is whether the code is correct.
It looks correct to me, but you should try it yourself to make sure it's working for you.
I'm guessing that rude reply was in response to my post. I don't care about the range either!
I was in fact showing you that through basic math you can simply subtract 10 INSTEAD of adding one and then flipping the sign.
Besides, you already know the answer.
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Advice: Take only as directed - If symptoms persist, please see your debugger
Linus Torvalds: "But it clearly is the only right way. The fact that everybody else does it some other way only means that they are wrong"
oh no sorry iMalc, I didn't meant to be rude 2 u
I just wanted 2 know whether the code is correct or not
Thanks 4 your help
i got it
