quick question regarding the '==' sign.

**MegaManZZ** · 01-10-2008

can you have a situation like

Code:

int a = 3;
int b = 3;
int c = 3;

if (a == b == c){
      cout<< "yes";
}

or does it have to be

Code:

if (a == b && a == c){
      cout<< "yes";
}

**laserlight** · 01-10-2008

It can be the former (but you may get a result which you did not expect), but it should be the latter.

**matsp** · 01-10-2008

The second one will do what you want. The first one does:

Code:

a == (b == c)

Which can be re-written as:

Code:

temp = (b == c);  // Makes a value of 0 or 1. (parenthesis not strictly necessary)
a == temp;

--
Mats

**Dino** · 01-10-2008

So, to clarify (for myself),

Code:

a==b==c ;

results in false, even through a==b is true and b==c is true. Correct?

Todd

**laserlight** · 01-10-2008

results in false, even through a==b is true and b==c is true. Correct?

Correct, except for special cases, e.g., a = b = c = 1.

Thread: quick question regarding the '==' sign.