testing for int or float

atoi typically returns 0 on failure, so if you check the string for 0, and it's FALSE, then that mean it's an invalid number.
But, oh crap, I was going to suggest that >_< Oh well.

Quote:

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Originally Posted by Elysia

atoi typically returns 0 on failure, so if you check the string for 0, and it's FALSE, then that mean it's an invalid number.
But, oh crap, I was going to suggest that >_< Oh well.

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Yeah, but what if the number the user entered IS 0? ;)

That's why I said check the input for 0.

Code:

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char buf[10];
cout << "Enter number: ";
cin >> buf;
if (atoi(buf) == 0 && buf[0] != '0'); // User did not enter 0, so it's not a number
if (atoi(buf) == 0 && buf[0] == '0'); // User actually did input 0.

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