Thread: Help with switcharoo program.

So I am writing this program that takes in two strings from console and then switches the vowels in string1 for the vowels in string two in order of ocurrance. For example:

text 1 = rapid
text 2 = ouch
result string = ropud

this is what i have so far:

Code:

#include "stdafx.h"
#include <iostream>
#include <string>
#include <cstring>


using namespace std;


bool isVowel (char);

void main()
{
	string text1, text2, translation;
	cin >> text1;
	cin >> text2;

	cout << "You entered: " << text1 << endl;
	cout << "You entered: " << text2 << endl;



	string result;
	int i1 = 0;
	int i2 = 0;

	//while ( i1 < s1Length() && i < s2Length())
	while ( i1 < text1.length() || i1 < text2.length())
	{
		for (;i1 < text1.length() && isVowel(text1[i1]) ; i1++)
		{
			if(i1 < text1.length())
				result += text1[i1];
		}
		cout << result;
	}
}

bool isVowel (char c)
{
	const string vowels = "aeiouAEIOU";
	for (int i = 0; i < vowels.length(); i++)
		if (c == vowels[i]){
			return true;}

		return false;
}

but I think there has got to be a better way of doing this. As of now, I am not sure what my next step should be or if the program is ok. Can anyone suggest anything or point out something I did wrong?

No, they are not guaranteed to have the same number of vowels. In this case, there is something else I have to do. For now, is there a way to make it work using some variation of the code i posted above?

Code:

#include "stdafx.h"
#include <iostream>
#include <string>
#include <cstring>


using namespace std;


bool isVowel (char);

int main()
{
	string text1;
	string text2;
	string result;
	cin >> text1;
	cout << text1 << endl;
	cin >> text2;
	cout << text2 << endl;

	for (int i =0; i < text1.length(); i++)
	{
		text1[i] = result[i];
	}
	for (int k =0; k < text2.length(); k++)
	{
		if (isVowel(text2[k]))
		{
			char b = text2[k];
			cout << b;
		}
		
		
	}
	
}

bool isVowel (char c)
{
	const string vowels = "aeiouAEIOU";
	for (int i = 0; i < vowels.length(); i++)
		if (c == vowels[i]){
			return true;}

		return false;
}

hk, is this the right track?

In pseudocode:

Code:

'v' = first vowel in string 2
For each letter 'x' of string 1:
    If 'x' is a vowel:
        Append 'v' to output
        'v' = next vowel in string 2
    Else:
        Append 'x' to output

Ok, I came up with this code but don't how to code that once the first vowel from 2 has been used, the program should seek a second vowel...

Code:

// vowel - Lab.cpp : Defines the entry point for the console application.

#include "stdafx.h"
#include <iostream>
#include <string>
#include <cstring>


using namespace std;


bool isVowel (char);

int main()
{
	string text1;
	string text2;
	string result;
	cin >> text1;
	cout << text1 << endl;
	cin >> text2;
	cout << text2 << endl;

	for (int i =0; i < text1.length(); i++)
	{
		if(isVowel(text1[i]))
		{
			for (int k = 0; k < text2.length(); k++)
			if (isVowel(text2[k]))
			{
				char b = text2[k];
				text1[i] = b;
				cout << text1 << endl;
				
			}
		}

	}
	
		
}

bool isVowel (char c)
{
	const string vowels = "aeiouAEIOU";
	for (int i = 0; i < vowels.length(); i++)
		if (c == vowels[i]){
			return true;}

		return false;
}

any suggestions?

anon, I am not sure how to accomplish that at the moment. can you give me an example and I will work from there.

Originally Posted by Fredir

anon, I am not sure how to accomplish that at the moment. can you give me an example and I will work from there.

Whether you should do what anon says depends on what your assignment says. What ARE you supposed to do when the number of values in string1 is more than the number of vowels in string2?