Help!

[ProgrammingDlux]

What's Up everyone, if anyone can help it would be appreciated.

My problem with this program (see output at very bottom) is that
I can use it once,and see one person's age, but when i try to input a second or third name after the first time, and press enter, the DOS Window closes on me. What can I do to keep this Program running for as long as I want?




#include <fstream.h>
#include <string.h>
#include <conio.c>

char response [10]; //not sure what this does (10)


int main()
{

cout << "\n Input the name Christian, Valerie, or Olivia to see their age.\n";
cin >> response;

while(strstr(response,"Christian")!=NULL)
{
cout << response << " is 20 years old.\n";
getch();
return 0;
}
while(strstr(response,"Valerie")!=NULL)
{
cout << response << " is 15 years old.\n";
getch();
return 0;
}
while(strstr(response,"Olivia")!=NULL)
{
cout << response << " is 8 years old.\n";
getch();
return 0;
}


return 0;
}


/*OUTPUT*************

Input the name Christian, Valerie, or Olivia to see their age
Christian (let's say i put this in)
Christian is 20 years old (this is the output)

[Shiro]

Let's take a look at just one while-loop:

while(strstr(response,"Christian")!=NULL) 
{ 
    cout << response << " is 20 years old.\n"; 
    getch(); 
    return 0; 
}

When entering this loop. It will print the output string and the response, then it will wait untill you press a key and then it returns 0. In other words, it prints something and after you've pressed a key, the program will finish.

By the way, I do not really see the meaning of strstr. It seems to me that you're comparing strings. In that case I would recommend using strcmp, a function which is written with the purpose to compare strings.

[golfinguy4]

By the way, I believe that it would be more efficient to use if statements. They were created for the purpose you want to use.