Thread: Help figuring out equation.

  1. #1
    Registered User
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    Sep 2007
    Posts
    23

    Help figuring out equation.

    How could I write these so that they would work?The "A" and the "F" work but the other 3 don't.

    Code:
    cout << "Letter Grades" <<endl;
    	for (int i = 0; i < MAXGRADES; i++)
    	{
    		if (grade[i]>89)
    			cout<<"A"<<grade[i];
    		if (90>grade[i]>79)
    			cout<<"B"<<grade[i];
    		if (80>grade[i]>69)
    			cout<<"C"<<grade[i];
    		if (70>grade[i]>59)
    			cout<<"D"<<grade[i];
    		if (grade[i]<60)
    			cout<<"F"<<grade[i];
    	}

  2. #2
    Deathray Engineer MacGyver's Avatar
    Join Date
    Mar 2007
    Posts
    3,210
    Use &&, which performs a logical AND on two arguments.

  3. #3
    Officially An Architect brewbuck's Avatar
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    Location
    Portland, OR
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    7,396
    The construct:

    Code:
    a > b > c
    Does not do what you think it does. Instead, use:

    Code:
    a > b && b > c

  4. #4
    Registered User
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    Sep 2007
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    23
    OK. Thanks. I should have known that!

  5. #5
    Registered User hk_mp5kpdw's Avatar
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    Jan 2002
    Location
    Northern Virginia/Washington DC Metropolitan Area
    Posts
    3,817
    This is all you should need:
    Code:
    cout << "Letter Grades" <<endl;
    for (int i = 0; i < MAXGRADES; i++)
    {
        if (grade[i]>89)
            cout<<"A"<<grade[i];
        else if (grade[i]>79)
            cout<<"B"<<grade[i];
        else if (grade[i]>69)
            cout<<"C"<<grade[i];
        else if (grade[i]>59)
            cout<<"D"<<grade[i];
        else
            cout<<"F"<<grade[i];
    }
    "Owners of dogs will have noticed that, if you provide them with food and water and shelter and affection, they will think you are god. Whereas owners of cats are compelled to realize that, if you provide them with food and water and shelter and affection, they draw the conclusion that they are gods."
    -Christopher Hitchens

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