There you go... C.exit = 1,and while it is equal to 1 it continuesCode:int main() { Program OMGDOIT; int y; C.exit = 1; while(C.exit == 1) { ....... ....... switch(y) { ........ ........ } clrscr(); //Clears screen maybe? } return 0; }
There you go... C.exit = 1,and while it is equal to 1 it continuesCode:int main() { Program OMGDOIT; int y; C.exit = 1; while(C.exit == 1) { ....... ....... switch(y) { ........ ........ } clrscr(); //Clears screen maybe? } return 0; }
So at the end of "case 7:" (before break) print the "C.exit" variable.
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Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
Like this I suppose?Code:case 7: OMGDOIT.Case7(); OMGDOIT.TerminationPrevention(); OMGDOIT.RorQ(); C.exit = 1;
Uhh...actually I found the problem...it has got nothing to do with C.exit or cin.ignore() or any of that crap...I forgot to put a break statement in Case 7 LOL
You mean this one:
case 7:
OMGDOIT.Case7();
OMGDOIT.TerminationPrevention();
OMGDOIT.RorQ();
break;
[/code]
It was in your original post, so I didn't look too carefully in the code you posted next - I should have...
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Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
In my original post, I ADDED the break statement thinking why it wasn't there..if only I had the brains to look in my original code :P
