Thread: Ending after do while loop

Hi, I've made a guess my number program and it ends straight after the while loop is met. And passes my cout thing after.

Code:

#include <iostream>
#include <ctime>
#include <cstdlib>

using namespace std;

int main()
{
    int guess;
    srand(time(0));
    int theNumber = rand() % 100 + 1;
    int tries = 0;
    
    cout << "Welcome to Ben's Guess My Number game!" << endl;
    
    do
    {
        cout << "Guess a number in between 0 and 100." << endl;
        cout << "Number: ";
        cin  >> guess;
        tries++;
        
        if (guess < theNumber)
        
                  cout << "Too low." << endl;
        
        
        if (guess > theNumber)
        
                  cout << "Too high." << endl;
        
        
    } while (guess != theNumber);
    
    cout << "Congratulations you guessed the number in " << tries << ", well done!" << endl;
    
    cout << "Press the return key to proceed...";
    cin.get();
    return 0;
        
    
    
    
}

Thanks ,
Ben

Thanks, it worked. But i'm still pretty confused. Whats the definition of buffer? What do you mean read in new line. Thanks again.

So, the cin places the input into the buffer, and when I use cin.get it reads from buffer and thinks somethings been pressed? Or am I way off lol.

You can use cin in different ways. You can use get(), ignore(), operator>>, getline, and other functions.

As laserlight said, when the user of your program types at the console, the console waits until the user hits enter. Then, all the characters the user typed, including a hidden newline character, are stored in the buffer.

When your program uses cin to read, it checks the buffer for data it needs. For example, if you use operator >> to read into an integer, cin checks the buffer for any data. At first, the buffer is empty, so the console waits for the user to type something and hit enter. Then cin sees the number the user typed and reads it in, then stops. The newline character is still in the buffer.

If you use operator>> again, it skips over whitespace characters automatically. That means the newline from the previous read is skipped, so you don't notice it. However, cin.get() reads differently. It gets a single character no matter what, meaning it does not skip over whitespace. At the end of your program, there is still a newline character in the buffer. The call to get() gets that newline character and returns immediately, so your window doesn't stay open.

If you call ignore(), it ignores the data in the buffer, which in this case is a newline. That leaves the buffer empty. Then you call cin.get() to get a character, but because the buffer is empty the console waits for the user to type in something and hit enter. While it is waiting the console window stays open so you can see the output, and then you hit enter and it closes.