Thread: Identifying 3x3 blocks (2d-array)

> for(count=0;count<210;count++)
This runs off the end of the array. Use < N, where N is the dimension of the array you're subscripting.
Or if there really are 70*3 elements, increase the size of your arrays to 210.

Code:

a b c  --> 69 more this way
d e f
g h i
|
|
v
69 more this way

Can you describe what you're trying to do with values 'a' to 'i' in this diagram.

Code:

for ( r = 0 ; r < 210 ; r += 3 ) {
  for ( c = 0 ; c < 210 ; c += 3 ) {
    // r and c index the 'a' element of each 3x3 cell
  }
}

i am trying to take e, and compare it to everything around it, ie a b c d f g h i to see if e is within one of everything around it. if it is within one then i want to display that block number, so (1,1) or wherever it may come up. and then look at the next block of 3x3 and so on and so forth.i will change the array size thanks

would i have to make a nested loops to examine each letter of ur diagram and include an if statement for the comparisons?

Something like

Code:

for ( r = 0 ; r < 210 ; r += 3 ) {
  for ( c = 0 ; c < 210 ; c += 3 ) {
    if ( isWithin( frequency, r, c ) && isWithin( intensity, r, c ) ) {
      printf( "Found\n" );
    }
  }
}

Have a go at writing the isWithin() function.

You are supposed to define it yourself.