Thread: Dinamic allocation for numberic types

Hello, I have a problem using dinamic allocation for numberic types. That's what I'm doing

Code:

//IDE = DevC++
//compiler = MingW
//compiled as cpp
#include <conio.h>
#include <stdio.h>
#include <stdlib.h>

typedef struct _DATA
{
double *dbl;
} DATA,*LPDATA;

int main()
{
double dbl;
DATA d;

d.dbl=(double*)malloc(sizeof(*d.dbl));
if(!d.dbl) {return 0;}
dbl=125.15f;
*d.dbl=dbl;
printf("%f %f\n",dbl,d.dbl);

free(d.dbl);
getch();
return 0;
}

The printf shows

Code:

125.150002 0.000000

My question is, ¿how should I setup a dynamic double value and be able to work with it? Maybe I'm missing something, but I have been thinking about it but I'm no able to find a working solution.

Thank's in advance
Niara

Hello manutd, Cactus_Hugger and swoopy, thank's for your help and time.

manutd: I have always the same problem: C synthax on C++ mode compilation. I like C but I compile as C++ because on certain moment I can do some 'debug' operations without the strict C model type (I say 'debug' operations, but also other things).

Cactus_Hugger: that was what I was missing. Because I usually work with dynamic (sorry for my english syntax) memory on char* types and that's always dereferenced; I forgot to use it here.

swoopy: I didn't kwon that but I know that compiler doesn't alert any error when omit the 'f' specifier on double types, I'll have in mind.


Bye and have a good day
Niara