some help here.

**epidemic** · 01-03-2007

Code:

int main ()
{
  int Choise;
  cout <<"Welcome! "<< endl;
  string loser ="";
  employee *Eptr = new workman (loser,loser,0,0);

  return 0;
}

compiles and runs fine.

Code:

int main ()
{  int Choise;
  cout <<"Welcome! "<< endl;

  employee *Eptr = new workman ("","",0,0);

  return 0;
}

does not compile and gives error:

"main.cpp": E2285 Could not find a match for 'workman::workman(char *,char *,int,int)' in function main() at line 31

why the ........ does this not compile!? it is like? the same thing annyway!

workman (string &fname,string &lname,int hours, double salary); => workman constructor
employee ( string &, string &, int = 0 , double = 0 ); => employee constructor

**dwks** · 01-03-2007

"" is a char*; string("") is a string. Use this

Code:

employee *Eptr = new workman (string(""),string(""),0,0);

or better yet overload employee() to support this

Code:

workman (char *fname,char *lname,int hours, double salary);

or maybe const char *s.

**Daved** · 01-03-2007

Your constructor takes a string reference that is not to const and a string literal cannot be converted to a plain reference. Make it const string& in your constructors.

**Boksha** · 01-03-2007

It's not the same thing. "string" is the name of a C++ class, while "" defines a constant character array.

Code:

int main ()
{  int Choise;
  cout <<"Welcome! "<< endl;

  employee *Eptr = new workman ("","",0,0);

  return 0;
}

is the same as

Code:

int main ()
{  int Choise;
  cout <<"Welcome! "<< endl;
  const char *loser ="";
  employee *Eptr = new workman (loser,loser,0,0);

  return 0;
}

Edit: whoah, that was quick.

**Daved** · 01-03-2007

>> char *loser ="";
This should be const char* loser = "".

But simply adding the const to the reference for the constructor parameters is the only change that needs to be made.

**epidemic** · 01-03-2007

ah yes, i was relooking in my book and it also shows a const string... ty guys :P that was quite quicky :P

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