cin.getline();

[wart101]

Need help please, why is it skipping cin.getline();

#include <cstdlib>
#include <iostream>
#include <fstream>

using namespace std;

struct data {
       
       int item;
       char Des[256];
       int qty;
       
       };

int main(int a, int b, char c[256])
{


char string[10];
data items;


cout<<"Please enter the item number > ";
cin>> a;
cout<<"Please enter the item's decription > ";
cin.getline(string,10);
cout<<"\nPlease enter the quantity on site > ";
cin>> b; 



0fstream  filea;
filea.open("test.txt",ios::app);



    
    
}

[Desolation]

I'd recommend you to use std::string over character arrays, but to solve your problem, you would need to insert a cin.ignore(1000, '\n); statement before the cin.getline() call.

[wart101]

I'd recommend you to use std::string over character arrays, but to solve your problem, you would need to insert a cin.ignore(1000, '\n); statement before the cin.getline() call.

Cheers, that worked but i'm still getting used to working with strings so i will just stick with what i am doing at the mo

[Daved]

The reason the ignore helps is that when th euser enters the item number, they time a number and hit enter. The number is read in but the enter is left around. Your next call to getline reads from cin and stops at the first newline (enter), so it stops write away. Adding the ignore causes all characters to be ignored up to and including the next newline, so the enter is ignored and getline can wait for the user to type the description.

[wart101]

#include <cstdlib>
#include <iostream>

using namespace std;

struct what{
       
       char jk[256];
       
       };

int main()
{
    
    char b[256];
    
    
    cout<<"decrip > ";
    cin.getline(b,256);
    
    what item;
    
    cout<< b;
    
    item.jk[256]=b[256];
    
    
    cout<< item.jk[256]; 
   
   
   cin.get();
   
   
   
    
    
    
    
    
    return 0;
    
}

Can anyone tell me what the hell i've done, it just outputs some crap from memory ( I think ), the answer is probably obvious but i can't see it. (I want to pass the variable in b to item.jk then display it through cout, but it comes out as jibberish?)

[swoopy]

> item.jk[256]=b[256];

> cout<< item.jk[256];

#include <cstring>
.
.
    strcpy(item.jk, b);    
    
    cout<< item.jk;

Another reason strings are recommended. To copy a string, it would just be:

    item.jk = b;

[Desolation]

You also went past the range of the array. For an array declared like this : array[256] you have indices ranging from 0 - 255, not 1 - 256.