Dear all , I have this problem, I need to set the path of a file object from the user using cin.getline, but I face a problem , please comment
Code:int main(int argc, char *argv[]) { char file_name[40]; if(argc == 1) {cout << "You can to pass in a file name to the program via the command line, " << " or type it down\n file : "; cin.getline(file_name,39); input_code.open(file_name); } else input_code.open(argv[1]); return 0; }
Try using std::strings.
please if you can suggest something
What are your errors/problems?
I don't know what is exactly, I'm usinf VC++ , when I run the program every thing is okay , but when I type the file name and press enter , unhandled excpetion error appears. and assembly code also
I could not see a problem in the code provided. What is the rest?
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
Odd, it works for me in Dev-C++. I can output and everything.
>it works for me in Dev-C++. I can output and everything.
what do you mean ?
I rely have this problem !
I mean I can compile it, run it, and even modify it to ouput stuff into the file. I'm assuming that above your code you have this:Code:#include <iostream> #include <fstream> using namespace std; fstream input_code;
yes ,
If I cancel the line
every thing wil be okay !Code:input_code.open(file_name);
Oh, oh:Maybe?Code:input_code.open(file_name, ios::trunc);
So what is your input? maybe it is longer than 39 characters?
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
no , its only 12 character , and the file exixts
still the same manutd
Are you using a relative path or an absolute path? Try putting the file on your c drive and typing C:/Filename.txt when asked for the filename.
