Thread: Cheque Printing Program Query

You just try to understand the code line-by-line so you can prove you did it yourself.

>Replace that line with something like this:
So you replace a good solution with a bad one? Woohoo! You know, if you had just included <limits> and <ios> to begin with (as you should have), it wouldn't have been an issue.

Well, I don't know about other compilers. I only have to use <iostream> for that to work.

karlawarla, try with including <limits> and <ios> then and put this line back there:

Code:

    std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');

>I only have to use <iostream> for that to work.
A lot of things "work". Only a small subset of those things are "correct". This is precisely the situation we try to avoid by being anal about standards.

Just try this:

Code:

#include <iostream>
#include <limits>
#include <ios>

char numbers[][10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
char numbers2[][10]={"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eightteen","nineteen"};
char numbers3[][10]={"","","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
void units(int u);

int main(){
    units(68);
    std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
}

void units(int u){
    if(u==0){
        std::cout<<numbers[0];
        return;
    }
    int nums[3]={0,0,0};
    bool plusand=false;
    nums[0]=(u/100)%10;
    nums[1]=(u/10)%10;
    nums[2]=u%10;
    for(int x=0;x<3;x++){
        if(nums[x]>0){
            if(plusand){
                std::cout<<"and ";
                plusand=false;
            }
            if(x==0){
                std::cout<<numbers[nums[0]]<<" hundred ";
                plusand=true;
            }
            else if(x==1){
                if(nums[1]==1){
                    std::cout<<numbers2[nums[2]];
                    break;
                }
                else{
                    std::cout<<numbers3[nums[1]]<<" ";
                }
            }
            else{
                std::cout<<numbers[nums[2]];
            }
        }
    }
    return;
}

Then use the previous code.

Anyway this should be the standard way and it seems you're missing some important headers.