Thread: Need help with this while loop, pretty please?

I have to set my cin's and cout's to work in a while loop. The way it is supposed to work is, the loop will end once someone enters "-999" as the int number... as you can see below. I have yet to add in the function call and other things, but I think I have come far enough to be able to ask this. I think if I put the cin << number; in the loop, it will not terminate because it will not check until it has gone thru everything. Can someone tell me what to do please?

Code:

#include <iostream>
#include <iomanip>

using namespace std;

double commission (double actualsales, double basesales, double compercent);
//function for the program


int main ()
        { //the int main has begun

        string name;
        int number;
        double basepay, compsales, printsales, compcom, printcom, totalcom, totalpay;

        cout << "Welcome to the APSU Computer Company Commission Statement program!" << endl;

        cout << "Please Enter Salesperson's Identification or -999 to terminate." << endl;
        cin >> number;

        cout << "Please Enter Salesperson's Name." << endl;
        cin.ignore (80, '\n');
        getline (cin, name);

        cout << "Please Enter Salesman Base Salary." << endl;
        cin >> basepay;

        cout << "Please Enter Personal Computer Sales." << endl;
        cin >> compsales;

        cout << "Please Enter Printer Sales." << endl;
        cin >> printsales;



        }//the int main has ended. oh my!

double commission (double actualsales, double basesales, double compercent)
        {//birth of a function
        double comm;
                if (actual sales > basepay)
                        {
                        comm = actualsales * compercent;
                        //and you get to keep your job :)
                        }
                else
                        {
                        comm = 0;
                        }
        return comm;
        }//death of a function

So? Check the number just after it is entered and exit the future loop if exit condition is matched.

if i put :

Code:

cin >> number;
while (number != -999)

it will never go back to the cin >> number;

if i put:

Code:

while (number != -999)
cin >> number;

it cant check the condition because it was never told what number was.

the prof said it had to be a while loop, no ifs

though I may be able to do a bool statement... not sure... shes not good at explaining

well i believe you guys when you post code for me, i just want to stay away from stuff she hasnt covered

you always can use something like that:

Code:

//enter number
...
while(number != -999)
{
      //do things
      ...
      //enter number
      ...
}

yes this is a copy of the assignment.. but the setw() parts wont show up in this forum

CSCI 1010 Programming Assignment 6



A. Purpose- Write a program that uses a function, loop, strings, output formatting.

B. Due Date- Due by 3 p.m. on Friday 10/27/06

C. Program Description – Name the program a6yourlastname.cpp




Write a C++ program to run on cscilinux2 for the following:

1) Read a three-digit salesperson identification number, a salesperson’s full name, a double base salary, and a double actual sales amount for each of the four categories.

2) Using a function, compute the commission earned in each of the two categories. The function should be passed the actual sales amount, the base sales, and the commission rate as a double. The function should return the commission which could be zero if the actual sales do not exceed the base sales.

3) Display the identification number, the salesperson’s full name, actual sales and base salary.

4) For each of the two categories, display the description, the sales amount, the commission amount.

5) Display the total commission paid to the employee and the total paid. All of the above must be in column format with the decimal points aligned.

6) Continue looping until -999 is inputted for Salesperson’s Number

Example:

Please Enter Salesperson’s Identification or -999 to Terminate
150

Please Enter Salesperson’s Name
Jane Doe

Please Enter Salesman Base Salary
1234.56

Please Enter Personal Computer Sales
5000.00

Please Enter Printer Sales
1000.00






APSU Computer Company

Commission Statement

SalesPerson 150

Jane Doe

********************************

Product
Sales Amount
Commission

Personal Computers
5000.00
100.00

Printers
1000.00
0.00





Total Commission

100.00

Base Pay

1234.56

Total Due

1334.56




Please Enter Salesperson’s Identification or -999 to Terminate -999

It seems that it must be the first input??? I would've used while(number != -999) when it would've been the last input...

O! my... so hard to change the first input to the last one?

Code:

int main (int argv, char* argv[])
{

        string name;
        int number;

        cout << "Welcome to the APSU Computer Company Commission Statement program!" << endl;

        cout << "Please Enter Salesperson's Identification or -999 to terminate." << endl;
        cin >> number;
        while(number != -999)
        {
        	double basepay, compsales, printsales, compcom, printcom, totalcom, totalpay;
        	cout << "Please Enter Salesperson's Name." << endl;
        	cin.ignore (80, '\n');
        	getline (cin, name);

        	cout << "Please Enter Salesman Base Salary." << endl;
        	cin >> basepay;

        	cout << "Please Enter Personal Computer Sales." << endl;
        	cin >> compsales;
        	cout << "Please Enter Printer Sales." << endl;
        	cin >> printsales;
        	//do your stuff here
        	//...


        	cout << "Please Enter Salesperson's Identification or -999 to terminate." << endl;
        	cin >> number;
       }
        return 0;
}