Thread: strlen in expressions

hi i am trying to make a program do this basically...

int * strlen / strlen * strlen * strlen = an int

i cannot figure out how to write that in code...

i don't know if you cannot use strlen in a "formula" ? or what?

thanks

mathatmatically

(5000 * 8) / (5 * 8 * 8)

obviously using varibles in the program

thanks again

Two methods:

Code:

int main( void )
{
	// USING *STRINGS

	char *C_Str1;
	char *C_Str2;
	char *C_Str3;
	char *C_Str4;
	
	// Intitalise the *strings

	std::cout<< (5000*strlen(C_Str1))/(strlen(C_Str2)*strlen(C_Str3)*strlen(C_Str4));



	// USING STD::STRING

	std::string one;
	std::string two;
	std::string three;
	std::string four;

	// Initalise the std::strings
	std::cout<< (5000 * one.size()) / (two.size() * three.size() * four.size());

	return 0;
}

Or something to that effect.

Try: x = (a*b)/(c*d*e);

= is for assignment, you can't assign a value to a mathematical calculation, that's why x that gets the value is on the left.

Also use brackets to make the statement non-ambigous.

ok thanks, that helps a lot, it works now anyways

sorry about the title, i will do better next time

thanks