Storing in an Array

**peckitt99** · 10-09-2006

i would like to know if i am on the right tracks or completely off the rails with this program. i need to Store the name in an array. Then ask for their surname. The program should declare a third array large enough to hold both names including a space between them. The names should both be copied to the third array (with a space between them) and the resultant array output to the screen. i amnot use any string library functions; manage the arrays yourself using loops to do the name copying and concatenation.

This is what i have got soo far and am stuck with the output the final array

Code:

char Fname[10];
char Lname2[10];
char FullName;
int i;

cout <<"enter your first name";

for (i=0; i<3; i++)
    {
    cin >> Fname[i];
    }
    
cout<<"Please enter you Second Name";

for (i=0; i<3; i++)
    {
    cin >>Lname2[i];
    }
    
for (i=0; i<20; i++)
{
cout << Fname[i] <<Lname2[i];
 }      
system("pause");
}

**maxorator** · 10-09-2006

Read it in with cin.getline().
Printf is a bit more comfortable to use.
Do not use system("pause"), look what I've used

Code:

#include <iostream>

int main(){
    char Fname[10];
    char Lname[10];
    char FullName;
    int i;
    printf("Enter your first name: ");
    std::cin.getline(Fname,10,'\n');
    printf("Enter your second name: ");
    std::cin.getline(Lname,10,'\n');
    printf("%s %s\n",Fname,Lname);    
    std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
}

**peckitt99** · 10-09-2006

with that code, is it copying it to array1 and array2 to array3? and i thought there were loops to get it to work then way the problem has been set out?

**maxorator** · 10-09-2006

No, there are 2 arrays.
It reads the first name to the first array and the last name to the second array.

**peckitt99** · 10-09-2006

ah right, but i need it to check the length cause i needed summat like

Code:

 for(i=0; i<10; i++)

or something like that. once it has checked the first array it stores it and then asks for the second name does the same thing, Then i need The names to both be copied to the third array (with a space between them) and the resultant array output to the screen.

**Kaiser** · 10-09-2006

Yes, but if you had taken the time to read his message, you would have known that was not what he wanted to do.

peckitt99:
In your code, Fullname cannot possibly store the concatenated string, since it is a char, not a char[]. You will need to copy the characters from the first string, until you encounter the null character, '\n'. Then you copy the white space, and then copy the characters from the second name until you encounter the null character.

**peckitt99** · 10-09-2006

KAISER is it possible for some example code to get me started on it?

**maxorator** · 10-09-2006

Now it does that:

Code:

#include <iostream>

int main(){
    char Fname[10];
    char Lname[10];
    char FullName[20];
    printf("Enter your first name: ");
    std::cin.getline(Fname,10,'\n');
    printf("Enter your second name: ");
    std::cin.getline(Lname,10,'\n');
    sprintf(FullName,"%s %s",Fname,Lname);
    printf("%s\n",FullName);    
    std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
}

**Kaiser** · 10-09-2006

First of all, you need to define Fullname as an array of 20 characters (including null termination), as 'char fullname[20];'. The loop(s) could be something like:

Code:

int i = 0;
while (Fname[i] != '\0') {
  Fullname[i] = Fname[i];
  i ++;
}
Fullname[i] = ' ';
i ++;
int j = 0;
while (Lname[j] != '\0') {
  Fullname[i] = Lname[j];
  j ++;
}

**peckitt99** · 10-09-2006

yeah that sound more familiar than maxorators code. ill give it a go n see how i go along

**Kaiser** · 10-09-2006

His code is perfectly correct, but as you said in the first post that you are not to use any built in string handling, it is not what you asked for.

**peckitt99** · 10-09-2006

i have got all the code working with all the other bits but am unsure how to input it all. i tried

Code:

Fullname[20] = Fname[i] + Lname[i]

the output i got from that was just the first name then a bunch of other characters.

**Kaiser** · 10-09-2006

I don't get the question. I though you wanted to 'cin >> Fname;' and 'cin >> Lname;', and then do the copying.

When working with arrays, the assignment operator does not do what you might think. When you learn about pointers you will know why.

**peckitt99** · 10-09-2006

well when i got the 2 names in the arrays i need to get the third array to output both the names and put in the space inbetween the Fname and Lname. if this makes any more sence?

**Kaiser** · 10-09-2006

The copying is already done, so you just output it. The entire program would look something like this:

Code:

int main() {
  char Fname[10];
  char Lname[10];
  char Fullname[20];
  cout << "First name: ";
  cin >> Fname;
  cout << "Family name: ";
  cin >> Lname;
  int i = 0;
  while (Fname[i] != '\0') {
    Fullname[i] = Fname[i];
    i ++;
  }
  Fullname[i] = ' ';
  i ++;
  int j = 0;
  while (Lname[j] != '\0') {
    Fullname[i] = Lname[j];
    i ++;
    j ++;
  }
  Fullname[i] = '\0';
  cout << Fullname << endl;
  return 0;
}

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