Thread: Help with program.

Well, I'm not going to write the whole thing , but the pseudo code's kinda like this:

Code:

1)Input class level
2)Input grade
3)Use a switch structure or nested if statements to check on appropriate results
4)Output pass or fail

hth

Thanks, I am having trouble with declaring the identifiers, it is the main thing that I get stuck with when writing code....it never fails that I will have trouble with that.

The identifiers?

Like

int x = 0;

???

yep, thanks though, I got the program to compile and run error free using the nested if statements, but I was trying to simplify it using the switch statement, I wrote a previous program for homework that had to calculate the change in quaters, dimes, nickesl and pennies for a given input from 0...99, so I wound up with about 100 lines of code. I had one if statement for each input because the out put would be different every time could this be simplified? Or not because of the different out put for every input? ie... 99 for input couts to 3 quaters, 2 dimes and 4 pennies.

As far as the current program is concerned I got it to work the same way as the first, but with this one I am sure I can simplify it using a switch statement with break. Here it is:

/*A grade calculation program that accepts a class
level and test score and computes the grade.*/

#include <iostream.h>

void main ()
{
int answer, y, x;
const int YES=1, NO=2;

cout<<"Would you like to begin grade";
cout<<" calculation?"<<endl;
cout<<"(1 - YES, 2 - NO)"<<endl;
cin>>answer;

while (answer==YES) {
cout<<"Please enter class level from 1";
cout<<" - 12";
cout<<" then press return."<<endl;
cin>>x;

cout<<"Please enter score and press";
cout<<" return."<<endl;
cin>>y;

if(x<=4 && y>=60)
cout<<"PASS"<<endl;

else if(x<=4 && y<60)
cout<<"FAIL"<<endl;

else if(x<=8 && x>4 && y>=75)
cout<<"PASS"<<endl;

else if(x<=8 && x>4 && y<75)
cout<<"FAIL"<<endl;

else if(x<=12 && x>8 && y>=90)
cout<<"PASS"<<endl;

else if(x<=12 && x>8 && y<90)
cout<<"FAIL"<<endl;

cout<<"Do you wish to continue?"<<endl;
cout<<"(1 - Yes, 2 - No)"<<endl;
cin>>answer;
}
}

Originally posted by jpad687
Here it is:

/*A grade calculation program that accepts a class
level and test score and computes the grade.*/

#include <iostream.h>

void main ()
{
int answer, y, x;
const int YES=1, NO=2;

cout<<"Would you like to begin grade";
cout<<" calculation?"<<endl;
cout<<"(1 - YES, 2 - NO)"<<endl;
cin>>answer;

while (answer==YES) {
cout<<"Please enter class level from 1";
cout<<" - 12";
cout<<" then press return."<<endl;
cin>>x;

cout<<"Please enter score and press";
cout<<" return."<<endl;
cin>>y;

Right here you could do this to save steps:

Code:

cout << "Enter class level and score: ";
cin >> x >> y;

if(x<=4 && y>=60)
cout<<"PASS"<<endl;

else if(x<=4 && y<60)
cout<<"FAIL"<<endl;
.
.
.

For these statements, one option is:

Code:

if (x <= 4)
  cout << (y >= 60 ? "PASS" : "FAIL");

cout<<"Do you wish to continue?"<<endl;
cout<<"(1 - Yes, 2 - No)"<<endl;
cin>>answer;
}
}

You could do other stuff, but that's a start.

LOL