Thread: C++ conversion

In general Roman numberals can be converted mathmatically
to their arabic equivalent by simply assiging a numerical value
to each letter, according to the chart below, and calculating a total.

M=1000|D=500|C=100|L=50|X=10|V=5|I=1

In code, could you show me how to along with comments convert
it.please help...much appreciated...

What bit are you stuck on?

As zen pointed out you are well on your way here. There are many ways to do this. But what the hell, here are a few:

Code:

/* way number one */
#define M 1000
#define D 500
#define C 100
//you ge the idea

/* way number two */
short M = 1000, D = 500, C = 100; //not too hard

There are also enumerations. You could also slap together some macros or functions to do simple opporations such as V + I = VI. But you will have make a function that returns a string for that sort of answer.

Well... think about it... just set up a loop to go along and pick up letterz:

Code:

#include <windows.h>
#include <stdio.h>
#define M 1000
#define D 500
#define C 100

int RomanToAribic(char *string)
{
     int ret = 0;
     for( int sloop = 0 ; sloop<strlen(string) ; sloop++ )
     {
          switch(toupper(string[sloop]))
          {
                 case 'M': ret += M; break;
                 case 'D': ret += D; break;
                 case 'C': ret += C; break;
                default: break;
          }
     }
}

void main()
{
        char rom[255];
         printf("Enter a roman number and I will spit back Aribic:");
         int r = RomanToAribic(rom);
         printf("\n%i",r);
// If I got it wrong and its * instead of + or something please correct me. :)
}

SPH

I asked to correct me if im wrong... so how does it work then?

SPH