Thread: Or operator?

  1. #16
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    >> Pop[index][11] = Pop[index][1]
    This part is wrong. It should be:

    then Pop[index][11] = 1 and fitness = 1.

  2. #17
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    Perhaps i should have been more clear, but yes.

    If the if statement is true, then Pop[index][11] = 1,

    what i need to know is does this part work as intended:

    (Grid[x-1][y] == 1)

    ie Grid[4][5] equal to 1

  3. #18
    The superhaterodyne twomers's Avatar
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    >> (Grid[x-1][y] == 1)

    Well, if x=5 and y=5, then it should work as intended.

  4. #19
    Cat without Hat CornedBee's Avatar
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    Code:
    if (Grid[x][++y] != 1 && Grid[x][y] != 0 /*|| Grid[x][y] != 3*/)
    This is a really bad idea. Although, due to the fact that && and || are sequence points, it will actually produce predictable results, it is still hard to read and thus hard to maintain.
    Just increment x/y first and then do the test.
    All the buzzt!
    CornedBee

    "There is not now, nor has there ever been, nor will there ever be, any programming language in which it is the least bit difficult to write bad code."
    - Flon's Law

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