Search for .txt file

**L_U_K_E** · 06-13-2006

I would like to know if there is any way that the user could enter a filename and have my program open the file.The thing is all of the files already exist and i want my prog to search for the file and then open it.

I was thinking maybe something like this:

Code:

case 1:
{
   cout<<"enter filename:";
   getline(cin,filename);
   ofstream a_file("Ingrediants\\"<<filename<<".txt";
   a_file>> information;
   a_file.close();
   cout<<information;
}

But im not sure this will work because of the:

Code:

   ofstream a_file("Ingrediants\\"<<filename<<".txt";

part of the file.

**laserlight** · 06-13-2006

I think it should be:

Code:

ofstream a_file(("Ingrediants\\" + filename + ".txt").c_str());

**SlyMaelstrom** · 06-13-2006

Code:

getline(cin,filename);
filename = "Ingrediants\\" + filename + ".txt";
a_file.open(filename.c_str());

EDIT: Though perhaps laserlight's suggestion would be better assuming you want to maintain the integrity of the original file name.

**L_U_K_E** · 06-13-2006

Thanx for both of your help ill try them when i get home(lol)!

**L_U_K_E** · 06-13-2006

Right i can now open the file but why wont this piece of code work:

Code:

getline(file1,info1);

this works

Code:

getline(cin,info1);

but this accepts user input but i want to read in the first line of the file and then do whatever with it(lol).

**jafet** · 06-13-2006

The << operator is only overloaded (overloaded == used for special things) for stream operations like cout and cin (and file objects you create). It's not a magic C++ function.

By the way, your line is missing a ")" in the end.

**laserlight** · 06-13-2006

Could be some problem with file1. How does it not work?

**L_U_K_E** · 06-13-2006

well afterwards i have the line:

Code:

cout<<info1;

however nothing is output onto the screen(??).

**L_U_K_E** · 06-13-2006

by the way i get the error message :

"no matching function to call to 'getline(std:

fstream&,std::string&)'

**laserlight** · 06-13-2006

getline() reads from an input stream. file1 is an output stream.

**L_U_K_E** · 06-13-2006

i get ya (i hope), so i just need to open the file for reading from then im sorted.But how do i do that??

**laserlight** · 06-13-2006

so i just need to open the file for reading from then im sorted

Use std::ifstream?

**jafet** · 06-13-2006

Have you made sure that your file was opened correctly?

Code:

ifstream file("foobar.txt");
if(!file.is_open() || file.bad())
{
    cout << "Unable to open file!\n";
}

**L_U_K_E** · 06-13-2006

Yeah i thought of that but im fairly new so well yeah!I'll try it.

**L_U_K_E** · 06-13-2006

yeah i ave checked to see if the file is open!

but i ave aother problem (sorry about this i said i was new to this)

Code:

                                      getline(file2,info);
                                      cout<<"Name:" + info << endl;
                                      getline(file2,info2);
                                      cout<<"Value:" + info2 << endl;
                                      getline(file2,info3);
                                      cout<<"Weight:" + info3 << endl;
                                      getline(file2,info4);
                                      cout<<"Effect 1:" + info4 << endl;
                                      getline(file2,info5);
                                      cout<<"Effect 2:" + info5 << endl;
                                      getline(file2,info6);
                                      cout<<"Effect 3:" + info6 << endl;
                                      getline(file2,info7);
                                      cout<<"Effect 4:" + info7 << endl;
                                      file2.close();
                                      cin.get();

I was wondering what is the matter with this as it doesn't print any of the information from the file!

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