Thread: how to fill multiple array locations with one input

  1. #1
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    how to fill multiple array locations with one input

    I am trying to fill an array with a large number using cin. What I would like to do it take a number like 123,456,789 and put it into someArray[0] = 123, someArray[1] = 456, etc. Can this be done easily?

  2. #2
    C++ Witch laserlight's Avatar
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    Can this be done easily?
    Probably. After all, it depends on what exactly you want to do. Are you trying to split by commas?
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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    Registered User Kurisu's Avatar
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    guess you could:

    1) Take the input as a character string instead of a number.
    2) Parse the character string.
    3) Convert string to an int before storing in the array.

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    Quote Originally Posted by laserlight
    Probably. After all, it depends on what exactly you want to do. Are you trying to split by commas?

    I need some way to seperate either by commas or seperate into 3 digit pieces after the fact.

  6. #6
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    You could just remove all the non-digit characters from the string, then read in three characters at a time.
    Code:
    #include <stdio.h>
    
    void J(char*a){int f,i=0,c='1';for(;a[i]!='0';++i)if(i==81){
    puts(a);return;}for(;c<='9';++c){for(f=0;f<9;++f)if(a[i-i%27+i%9
    /3*3+f/3*9+f%3]==c||a[i%9+f*9]==c||a[i-i%9+f]==c)goto e;a[i]=c;J(a);a[i]
    ='0';e:;}}int main(int c,char**v){int t=0;if(c>1){for(;v[1][
    t];++t);if(t==81){J(v[1]);return 0;}}puts("sudoku [0-9]{81}");return 1;}

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