Thread: New to CPP -> convert Object to String

  1. #1
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    New to CPP -> convert Object to String

    I'm confused by the pointers..

    Code:
    RegistryKey * pRegKey = Registry::LocalMachine;
    pRegKey = pRegKey->OpenSubKey(L"SOFTWARE\\MySoft");
    Object *pValue = pRegKey->GetValue(L"InstallDir");
    Console::WriteLine(L"Directory: {0}", pValue);
    Ok, so I need to convert pValue to a string or char*.. I can't figure out how to do that..

    I tried
    Code:
    std::cout(pValue->ToString);
    But i get this error:

    error C2064: term does not evaluate to a function

  2. #2
    Devil's Advocate SlyMaelstrom's Avatar
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    "cout" isn't a function, so your last statement is incorrect. I also have no idea what the "Object" object is refering to, perhaps you can post what libraries you're using or the code for the "Object" class if you wrote it yourself.
    Sent from my iPadŽ

  3. #3
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    Yes, I messed up, srd::cout(blah) is wrong..

    Code:
     std::cout << pValue->ToString;
    This just displays 1..

    No I don't have any class named Object.. pRegKey->GetValue(L"InstallDir"); This returns a type-Object.. Hence:

    Code:
    Object *pValue = pRegKey->GetValue(L"InstallDir");
    .. But i don't understand why *pValue (pointer) instead of just pValue..

    This is all I'm including:

    Code:
    #using <mscorlib.dll>
    using namespace System;
    using namespace Microsoft::Win32;
    
    #include <string>
    #include <iostream>
    #include <stdio.h>
    #include <conio.h>

  4. #4
    Devil's Advocate SlyMaelstrom's Avatar
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    Quote Originally Posted by smash84
    Code:
    #using <mscorlib.dll>
    using namespace System;
    using namespace Microsoft::Win32;
    You may get better answers in the Windows Programming forum. Don't repost, though, a moderator will move it if they feel it to be nessassary.
    Sent from my iPadŽ

  5. #5
    Frequently Quite Prolix dwks's Avatar
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    Code:
    #include <stdio.h>
    In C++ the standard C libraries have been renamed by dropping the trailing .h and adding a leading 'c', so the above include should be
    Code:
    #include <cstdio>
    If your compiler doesn't have <cstdio>, get Dev-C++.

    Perhaps google can answer your question: http://www.google.ca/search?hl=en&q=...o+String&meta=
    dwk

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  6. #6
    semi-colon generator ChaosEngine's Avatar
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    Quote Originally Posted by smash84
    Code:
    #using <mscorlib.dll>
    using namespace System;
    using namespace Microsoft::Win32;
    you are using either managed C++ or C++/CLI. This is the C++ binding to .net and as such, non-standard.

    anyway ToString is a method. you need to call it like so
    Code:
     std::cout << pValue->ToString();
    but I'm not even sure that will work as ToString returns a .Net String object instead of a std::string.
    "I saw a sign that said 'Drink Canada Dry', so I started"
    -- Brendan Behan

    Free Compiler: Visual C++ 2005 Express
    If you program in C++, you need Boost. You should also know how to use the Standard Library (STL). Want to make games? After reading this, I don't like WxWidgets anymore. Want to add some scripting to your App?

  7. #7
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    This compiles, but still only prints 1:

    Code:
    std::cout << pValue->ToString();
    I've also changed include to: #include <cstdio> instead of #include <stdio.h>

    Also, why won't this compile:

    Code:
    String hello = pValue->ToString();
    ?

    'hello' : 'System::String' differs in levels of indirection from 'char [50]'

    CONFUSING!!!

  8. #8
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    Code:
    pValue->ToString();
    Those error probably mean that the return value of the above expression is in the .NET's own type, which is incompatible with std:: C++ classes and functions. Looks like you'll have to go .NET all the way (which is probably what they wanted you to do in the first place).
    Code:
    #include <stdio.h>
    
    void J(char*a){int f,i=0,c='1';for(;a[i]!='0';++i)if(i==81){
    puts(a);return;}for(;c<='9';++c){for(f=0;f<9;++f)if(a[i-i%27+i%9
    /3*3+f/3*9+f%3]==c||a[i%9+f*9]==c||a[i-i%9+f]==c)goto e;a[i]=c;J(a);a[i]
    ='0';e:;}}int main(int c,char**v){int t=0;if(c>1){for(;v[1][
    t];++t);if(t==81){J(v[1]);return 0;}}puts("sudoku [0-9]{81}");return 1;}

  9. #9
    Registered User Jaqui's Avatar
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    #include <iostream>
    #include <stdio.h>
    these are supplying the same functions, the c and the c++ versions. you don't need both in any application, unless to want conflicts to crash it.
    Quote Originally Posted by Jeff Henager
    If the average user can put a CD in and boot the system and follow the prompts, he can install and use Linux. If he can't do that simple task, he doesn't need to be around technology.

  10. #10
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    No nothing, I still get '1' instead of the string.. Can't figure out how to solve this problem..

    Anyone know a better way to access registry key values?

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