Thread: basic code help

  1. #1
    Registered User
    Join Date
    May 2006

    basic code help

    Hey, I am new to programming and I was trying to make a basic add program. It is working fine until it asks you if you want to do it again and no matter if I push y or n it does nothing. What am I missing?

    #include <iostream>
    using namespace std;
    int mult (int a, int b);
    int main()       //Trying to make a basic add program. After you add will ask if you want 
    {                //to do another problem but isn't. to try and simplize the program erased 
        int a;       //code to make program repeat when you do again and simply put it works 
        int b;       //until i can find out why if statement is not working. 
        char  y, n;
        cout<<"Please input the two numbers to be added: ";  
        cin>> a >> b;
        cout<<"  The sum of the two numbers is: "<< mult (a, b) <<"\n";
        cout<<"Would you like to add again? (y/n): ";
        cin>> y >> n;
        if ( y == y )  {
        cout<<"It works\n";
    int mult (int a, int b)
             return a + b;

  2. #2
    Lurking whiteflags's Avatar
    Join Date
    Apr 2006
    United States
    int a = 0, b = 0;
    char again = 'y'; // Well the user is only going to be making one choice
                      // so it needs just one variable
    while(again != 'n') {    // make sure you compare it to a character
       cout<< "Please enter two digits to add: ";
       cin>> a >>b;
       cout<< "The sum is " <<add(a, b) <<endl;
       cout<< "Got another problem? ";
       cin>> again;
    Something like that.
    Last edited by whiteflags; 05-20-2006 at 01:51 AM.

  3. #3
    Advanced Novice linucksrox's Avatar
    Join Date
    Apr 2004
    when you ask the user if they want to repeat, you only need to input into one char and check to see if that's 'y'. so get rid of the n variable, change cin >> y >> n; to cin >> y; and then your if statement, put single quotes around the second y so that it compares the contents of the y variable to the character y. if (y == 'y'). otherwise it checks to see if y is equal to itself, which will always be true.
    "What are all you parallelograms doing here?" - Peter Griffin (to Joe and his wheelchair buddies)

  4. #4
    The superhaterodyne twomers's Avatar
    Join Date
    Dec 2005
    >> if ( y == y )

    should be

    if ( y == 'y' )

  5. #5
    Frequently Quite Prolix dwks's Avatar
    Join Date
    Apr 2005
    citizen's code it a perfect candidate for a do-while loop.

    Seek and ye shall find. quaere et invenies.

    "Simplicity does not precede complexity, but follows it." -- Alan Perlis
    "Testing can only prove the presence of bugs, not their absence." -- Edsger Dijkstra
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