Thread: Pointers and their Addresses

/* ok my question is the following let's say you declare a variable and itialize it.....and then you assign the address of that variable to a pointer, wouldn't the address of the pointer then be the same as the address of the variable that was created?Cosider the following:*/


#include <iostream>
#include <stdlib.h>
using namespace std;
int main()

{
int yourAge=15; //yourAge is initialized
cout<<"The address of yourAge is "<<&yourAge<<endl;
int *yourAgeManipulation=&yourAge; /*pointer is created and assigned your Age's
address */

cout<<"The addres of *yourAgeManipulation is"<<&yourAgeManipulation<<endl;/*Shouldn't *yourAgeManipulation have the same address as that of youAge. If it should tell me why if not please tell me why as well.*/

system("PAUSE");
return 0;
}

/*#####################################*/
OUTPUT:
The address of yourAge is 0x254fdd4
The addres of *yourAgeManipulation is0x254fdd0
Press any key to continue . . .

although the two address do look pretty close........please help

Change

cout<<"The addres of *yourAgeManipulation is"<<&yourAgeManipulation<<endl;

to

cout<<"The addres of *yourAgeManipulation is"<<yourAgeManipulation<<endl;

And you will get a more expected result

Notice how the differences between the memory addresses is the same size as an int

In C++ the alias &reference operator, however, does create an object which basically IS the referenced object(same memory location).

int num = 10;

int &nic = num;

nic = 15;

//...now num = 15

Unlike the pointer, an alias must cannot point to any other object , and must be initialized at the time of creation.

Yeah I guess they can't occupy the same space that's true....I think I get it know though the value of *yourAgeManipulation is the address of your age.

Please tell me if I am right or not.

Exactly.